Mechanical · mechanisms

Gear Train Calculator

Ratio, output speed and torque through up to three meshed stages.
ratio = N_driven / N_driver
9.0:1 reduction

Train type

Gears on parallel fixed shafts. Every external mesh reverses direction.

Input shaft

Gear stages

up to 3

Physical size

Mesh efficiency

Train schematic

speed
Output shaft
Detail
StageDriver TDriven TRatioDirection flip
How it works

Power stays (almost) constant

Ratio per stage

Each stage is driven teeth ÷ driver teeth; the overall ratio is the product. A mesh trades speed for torque, not power: P = τω.

Every mesh flips

Each external mesh reverses direction: an even number of stages turns the output the same way as the input, an odd number reverses it.

Planetary: three ratios

Sun, planets and ring on one axis have two independent speeds, so it is not a ratio until you hold something. Hold a different member, get a different ratio.

Undercut

Below 2/sin²α teeth (17.1 at 20°) a standard cutter gouges the tooth root, thinning the section that carries the load.

Worked example. A motor at 1,750 rpm and 10 N·m feeds two 3:1 reduction stages (20→60 teeth, then 15→45) for a 9:1 overall ratio: output speed drops to 194 rpm while ideal torque rises to 90 N·m. Two direction flips mean the output turns the same way as the input. The first two bars are speed, the last two torque. A 24-tooth sun in a 72-tooth ring gives 4:1, 1.33:1 or −3:1 depending only on which member is held.
Field notes

Gearing up and gearing down

Why a planetary set is different

A simple train puts every gear on its own fixed shaft. A planetary set puts sun, planets and ring on one axis, with the planets on an arm: three usable connections instead of two. It is how an automatic gearbox changes ratio without moving a gear. A gear pair has one input and one output; a planetary set has three shafts and only two independent speeds, which is exactly what a differential is for.

− 3 : 1

The ring gear does not reverse

Every external mesh reverses direction; an internal one does not, because the teeth face inward. Hold the ring and the sun and carrier turn the same way. Hold the carrier instead and the ring reverses: the one arrangement here that gives a negative ratio.

(R − S) / 2

Ring minus sun must be even

The planet must fill the gap exactly: its tooth count is (ring − sun) ÷ 2, so an odd difference asks for half a tooth. Separately, sun + ring must divide by the number of planets or the last lands where a tooth should be; three planets suit most counts, five often fails. Both are assembly constraints: the ratio looks fine either way.

17.1 / 31.9teeth

Why 17 teeth keeps coming up

The limit is 2/sin²α: 17.1 at 20° but 31.9 at 14.5° (why old imperial gearing looks so much coarser) and about 12 at 25°. On a small enough gear the rack tip sweeps inside the base circle and scoops the root. Profile shift can rescue a smaller pinion; a plain full-depth cutter cannot.

Reduction, overdrive, idlers, compound trains

A ratio above 1:1 reduces speed and multiplies torque; below 1:1 does the reverse (a bicycle final drive, a wind-turbine generator stage). An idler cancels out of the ratio but adds one direction flip. Stacking stages on shared shafts (this tool’s model) multiplies ratios; several gears on one shaft meshing with a single larger gear is a different, true compound topology used to fit a big ratio into a small space. A single 50:1 spur stage needs a driven gear 50× the driver’s diameter, so splitting it keeps every gear a sane size.

Module, pitch and efficiency

Meshing gears must share module (metric) or diametral pitch (imperial), so an odd tooth count is not always drop-in. Sliding friction and churning bleed a few per cent per mesh: 96–99% for well-cut spur and helical gears, but worm meshes can be 50–90%. Output torque is an upper estimate.

Questions

What people ask

Why does torque go up when speed goes down?

Because the driven gear has more teeth meshing over the same distance, each tooth on the smaller driver has to push harder to keep the tangential mesh force consistent — more teeth sharing that force means more total leverage, which shows up as torque.

What's an idler gear, and does it change the ratio?

A gear inserted between driver and driven purely to reverse direction or bridge a gap — its own tooth count cancels out of the ratio math entirely (it appears once as a "driven" and once as a "driver"), but it does add one more direction flip.

Why not just use one huge gear ratio in a single stage?

Practical tooth counts and centre distances get unwieldy fast — a single 50:1 spur stage needs a driven gear 50× the driver's diameter. Splitting the same overall ratio across two or three stages keeps every gear a sane, manufacturable size.

Why is efficiency less than 100% per stage?

Sliding friction between meshing teeth, plus some churning loss from lubricant, bleeds off a few percent of power at every mesh — well-cut spur and helical gears typically manage 96–99% per stage; worm gear meshes can be far lower, sometimes 50–90%.

How do I calculate gear ratio?

Ratio = Ndriven ÷ Ndriver, the teeth on the driven gear over the teeth on the driver. A 20-tooth pinion driving a 60-tooth gear is 3:1: the output turns at a third of the speed with up to three times the torque, less friction losses. For several stages multiply the stage ratios, so 3:1 then 4:1 is 12:1.

Ideal mesh geometry. Real gear trains lose a little more to bearing friction and lubricant drag than the mesh efficiency alone accounts for — treat output torque as an upper estimate.
Version history · 1 release
  1. v1.652026-08-07Gear train gains planetary gearing, physical sizing and the undercut limit — 3 new rules

Releases in which this page changed, newest last. Derived from the archived copy of every release, not from notes written afterwards — so it reflects what actually shipped. Site-wide passes are left out; they are in the full changelog.

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